Motion of particle is given by equation
`s=(3t^(3)+7t^(2)+14t+8)m`
The value of acceleration of the particle at t = 1 s is

Motion of particle is given by equation s=(5t^(3)+3t^(2)+8t+17)m The value of acceleration of the particle at t = 2 s is

Motion of a particle is given by equation S = (3t^(3) + 7 t^(2) + 14 + t + 8) m, The value of acceleration of the particle at t = 1 sec, is:

Motion of a particle is given by equation S = (3t^(3) + 7 t^(2) + 14 + t + 8) m, The value of acceleration of the particle at t = 1 sec, is:

A particle moves along a straight line such that its displacement at any time t is given by s = 3t^(3)+7t^(2)+14t + 5 . The acceleration of the particle at t = 1s is

A particle moves along a straight line such that its displacement at any time t is given by s = 3t^(3)+7t^(2)+14t + 5 . The acceleration of the particle at t = 1s is

The angular displacement of a particle is given by theta =t^3 + t^2 + t +1 then,the angular acceleration of the particle at t=2 sec is ……. rad s^(-2)

The displacement of a particle in time 't' is given by S = t^(3) - t^(2) - 8t =18 . The acceleration of the particle when its velocity vanishes is

The velocity time relation of a particle is given by v = (3t^(2) -2t-1) m//s Calculate the position and acceleration of the particle when velocity of the particle is zero . Given the initial position of the particle is 5m .

The velocity time relation of a particle is given by v = (3t^(2) -2t-1) m//s Calculate the position and acceleration of the particle when velocity of the particle is zero . Given the initial position of the particle is 5m .