" (i) "(2xy)/(x+y)=(3)/(2),(xy)/(2x-y)=(-3)/(10);x+y!=0,2x-y!=0

Solve the following pairs of equations: (2xy)/(x+y)=(3)/(2), (xy)/(2x-y)=(-3)/(10), x, y ne 0, 2x-y ne 0

Solve the following pair of equations: (2xy)/(x+ y)= (3)/(2), (xy)/(2x- y)= (-3)/(10), x+y ne 0, 2x-y ne 0

(xy)/(x-y)=(1)/(2);(xy)/(x+y)=(1)/(5) wherex +y!=0;x-y!=0

Solve : {:((2xy)/(x+y)=(3)/(2)),((xy)/(2x-y)=-(3)/(10)):} x+y ne 0 and 2x-y ne 0

Veriffy : (i) x^(3)+y^(3)=(x+y)(x^(2)-xy+y^(2))x^(3)-y^(3)=(x-y)(x^(2)+xy+y^(2))

(3xy+y^(2))dx+(x^(2)+xy)dy=0

The factors of x^(3)-x^(2)y-xy^(2)+y^(3) are (a (x+y)(x^(2)-xy+y^(2))(b)(x+y)(x^(2)+xy+y^(2))(c)(x+y)^(2)(x-y)(d)(x-y)^(2)(x+y)

On simplification, (x^3-y^3)/(x[(x+y)^2-3xy]) div (y[(x-y)^2+3xy])/(x^3+y^3)xx ((x+y)^2-(x-y)^2)/(x^2-y^2) is equal to : सरलीकरण के बाद, (x^3-y^3)/(x[(x+y)^2-3xy]) div (y[(x-y)^2+3xy])/(x^3+y^3)xx ((x+y)^2-(x-y)^2)/(x^2-y^2) किसके बराबर होगा?

Solution of D.E (dy)/(dx)=(2x+5y)/(2y-5x+3) is,if (y(0)=0) (1) x^(2)-y^(2)+5xy-3y=0 (2) x^(2)+y^(2)+5xy-3y=0 (3) x^(2)-y^(2)+5xy+3y=0 (4) x^(2)-y^(2)-5xy-3y=0

If A=(x^3+y^3)/((x-y)^2+3xy), B=((x+y)^2-3xy)/(x^3-y^3), C=(xy)/(x^2-y^2) then (A-:B)xxC=