" (b) "(1)/(b)+(1)/(a-b)-(1)/(b-c)=0

(1)/(a)+(1)/(c)+(1)/(a-b)+(1)/(c-b)=0 and b!=a+c, then a,b,c are in

If (1)/(a)+(1)/(a-b)+(1)/(c)+(1)/(c-b)=0 and a+c-b!=0, then prove that a,b,c are in H.P.

If (1)/(a)+(1)/(a-2b)+(1)/(c)+(1)/(c-2b)=0 and a,b,c are not in A.P.then

If a,b,c are in H .P.then (1)/(a)+(1)/(b+c),(1)/(b)+(1)/(a+c),(1)/(c)+(1)/(a+b) are in

If (b+c)/(a), (c+a)/(b), (a+b)/(c ) are in A.P. show that (1)/(a), (1)/(b), (1)/(c ) are also in A.P. (a+b+c != 0) .

a,b,c,a+b+c!=0 and (1)/(a)+(1)/(b)+(1)/(c)=(1)/(a+b+c) ,then is ((a+b+c)^(5))/(a^(5)+b^(5)+c^(5)) is

If a,b,c are in A.P then a((1)/(b) + (1)/(c )), b ((1)/(c ) + (1)/(a)), c ((1)/(a ) + (1)/(b)) are in

If a ((1)/(b) + (1)/(c)) , b((1)/(c) + (1)/(a)) , c ((1)/(a)+ (1)/(b)) are in AP then a, b, c are in :