5(y^(3)-y^(2)+ya+y-a-1

((y^(3)-3y^(2)+5y-1)/(y-1))

Subtract : 5y^(4) - 3y^(3) + 2y^(2) + y - 1 from 4y^(4) - 2y^(3) - 6y^(2) - y + 5

Divide: (2y^(2) - 3y^(3) + 5y-4) // (y-1)

Find the following products and verify the result for x=-1,y=-2:(3x-5y)(x+y)(2)(x^(2)y-1)(3-2x^(2)y)((1)/(3)x-(y^(2))/(5))((1)/(3)x+(y^(2))/(5))

Simplify : (i) (5x - 9y) - (-7x + y) (ii) (x^(2) -x) -(1)/(2)(x - 3 + 3x^(2)) (iii) [7 - 2x + 5y - (x -y)]-(5x + 3y -7) (iv) ((1)/(3)y^(2) - (4)/(7)y + 5) - ((2)/(7)y - (2)/(3)y^(2) + 2) - ((1)/(7)y - 3 + 2y^(2))

Find the remainder when the polynomial y^3 -3y^2 +5y -1 is divided by (y-1) . p(y) =………. p(1) = …………….=………..=………………

-7y + y^(5)+3y^(3)-1/2 + 2y^(4)-y^(2) write the polynomials in standard form.

If (x^2+x)+i ya n d(-x-1)-i(x+2y) are conjugate of each other, then real value of x&y are x=-1,y=1 b. x=1,y=-1 c. x=1,y=1 d. x=-1,y=-1