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" 25"sec^(-1)(tan2x)...

" 25"sec^(-1)(tan2x)

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sec^(-1)((1+tan^(2)x)/(1-tan^(2)x))

sec^(2)2x=1-tan2x

sec^(2)2x=1-tan2x

sec^-1((1+tan ^2x)/(1-tan ^2 x))

sec^-1((1+tan ^2x)/(1-tan ^2 x))

Solve the equation sec ^(2)2x=1-tan2x

Find the general solution : quad sec^(2)2x=1-tan2x

Find the general solution of the following equations : sec^(2)2x=1-tan2x

If tan y = (tan x+sec x-1)/(tanx -sec x+1) show that (dy)/(dx) = 1/2

If tan y=(tan x+sec x-1)/(tan x-sec x+1) show that (dy)/(dx)=(1)/(2)