Two vectors `vecA" and "vecB` have equal magnitudes. If magnitude of `vecA+vecB` is equal to n times the magnitude of `vecA-vecB`, then the angle between `vecA" and "vecB` is :-

Two vectors vec A and vecB have equal magnitudes.If magnitude of (vecA+vecB) is equal to n times of the magnitude of (vecA-vecB) then the angle between vecA and vecB is :-

The resultant of two vectors vecA and vecb is perpendicular to the vector vecA and its magnitude is equal to half the magnitude of vector vecB . The angle between vecA and vecB is

Two vectors vecA and vecB have precisely equal magnitudes. For the magnitude of vecA + vecB to be larger than the magnitude of vecA- vecB by a factor n, what must be the angle between them ?

The resultant of two vectors vecA and vecB is perpendicular to vecA . Magnitude of Resultant vecR is equal to half Magnitude of vecB . Find the angle between vecA and vecB ?

The resultant of two vectors vecA and vecB is perpendicular to the vector vecA and its magnitude is equal to half of the magnitude of the vector vecB . Find out the angles between vecA and vecB . .

The resultant of two vectors vecA and vecB is perpendicular to the vector vecA and its magnitude is equal to half of the magnitude of the vector vecB . Find out the angles between vecA and vecB . .