If 60 % of a first order reaction was completed in 60 minutes, 50 % of the same reaction would be completed in approximately
[log = 4 = 0.60, log 5 = 0.69].

If 60% of a first order reaction was completed in 60 min, 50% of the same reaction would be completed in approximately

75% of a first order reaction is completed in 32 minutes. 50% of the reaction would have been completed in

If 75% of a first order reaction was completed in 90 minutes, 60% of the same reaction would be completed in approximately ( in minutes)... (Take :log2=0.3;log2.5=0.40 )

If 75% of a first order reaction was completed in 90 minutes, 60% of the same reaction would be completed in approximately (in minutes ) .............. (Take : log 2 = 0.30 , log 2.5 = 0.40)

If 75% of a first order reaction was completed in 90 minutes, 60% of the same reaction would be completed in approximately (in minutes ) .............. (Take : log 2 = 0.30 , log 2.5 = 0.40)

If 75% of a first order reaction was completed in 60 minutes, 50% of the same reaction under the same conditions would be completed in

60% of a first order reaction was completed in 60 minutes. When was it half completed ?