sin(3 theta+alpha)+sin(3 theta-alpha)+sin(alpha-theta)-sin(alpha+theta)=cos alpha

sin(3theta+alpha)+sin(3theta-alpha)+sin(alpha-theta)-sin(alpha+theta)=cosalpha

sin(3theta+alpha)+sin(3theta-alpha)+sin(alpha-theta)-sin(alpha+theta)=cosalpha

sin(3theta+alpha)+sin(3theta-alpha)+sin(alpha-theta)-sin(alpha+theta)=cosalpha

cos ( theta + alpha)* cos ( theta - alpha) + sin ( theta + alpha) * sin (theta - alpha )=

Simplify be reducing to a single term : cos (theta + alpha ) cos ( theta - alpha ) - sin ( theta + alpha ) sin (theta - alpha).

If sin^(2)(theta-alpha)cos alpha=cos^(2)(theta-alpha)sin alpha=m sin alpha cos alpha, then

if sin(theta+alpha)=cos(theta+alpha) then tan alpha

Prove that cos 4theta–cos 4alpha = 8(cos theta-cos alpha)(cos theta+ cos alpha )(cos theta -sin alpha)(cos theta+sin alpha)

If sin(theta+alpha)=n sin(theta-alpha) , prove that cot theta=(n-1)/(n+1) cot alpha .