" U) "(3-2x)(3+2x)

U = 2x^(3) - 2x^(3) - 6x^(2) + 5x , where x is in metres and U is the potential energy which depends on x. Selsct the correct option.

Let u and v be two functions defined on R as u(x)=2x-3 and v(x)=(3+x)/2 .Prove that u and v are inverse to each other.

If u =x ^(3) +2xy^(2) -x ^(2)y show that (del^(2)u)/(delxdely) =(del^(2)u)/(delydelx).

If u = x^(4) + y ^(3) + 3x ^(2) y^(2) + 3x ^(2) y find (del u)/(delx), (delu)/(dely), (del^(2) u)/(delx^(2)) , (del^(2)u)/(delx dely).

If u = (x-3)/( 2) and v= ( y-2)/( 3), then cov(u,v) = k cov(x,y) . The value of k is

Differentiate the following w.r.t. x or t or u as the case may be: 7. y= (2x -3)/( 3x + 4)

The potential enery of a particle varies with posiion x according to the relation U(x) = 2x^(4) - 27 x the point x = (3)/(2) is point of

The potential enery of a particle varies with posiion x according to the relation U(x) = 2x^(4) - 27 x the point x = (3)/(2) is point of

If f(2x+3y ,2x-7y)=20 x ,t h e nf(x , y)e q u a l sdot 7x-3y 7x+3y 3x-7y (d) x-k y

(x-y)(1-(dy)/(dx))=e^(y), where x-y=u A) ue^u-e^u=e^(x)+c B) u^(2)=e^(x)+c C) u^(2)=(1)/(2)e^(x)+c D) u^(2)e^(x)=2x+c