If `a=(sqrt(3))/2` , then `sqrt(1+a)+sqrt(1-a)=?` `(2-sqrt(3))` (b) `(2+sqrt(3))` (c) `((sqrt(3))/2)` (d) `sqrt(3)`

(sqrt(3)-sqrt(2))(1)/(sqrt(3))

sqrt((4)/(3))-sqrt((3)/(4))=?(4sqrt(3))/(6) (b) (1)/(2sqrt(3))(c)1(d)-(1)/(2sqrt(3))

Simplify (i) (4+ sqrt(5))/(4-sqrt(5))+(4-sqrt(5))/(4+sqrt(5)) (ii) (1)/(sqrt(3) + sqrt(2)) - (2)/(sqrt(5)-sqrt(3)) -(2)/(sqrt(2) - sqrt(5)) (iii) (2+sqrt(3))/(2-sqrt(3)) + (2-sqrt(3))/(2+sqrt(3)) + (sqrt(3)-1)/(sqrt(3)+1) (iv) (2+sqrt(6))/(sqrt(2)+sqrt(3))+(6sqrt(2))/(sqrt(6)+sqrt(3)) -(8sqrt(3))/(sqrt(6)+sqrt(2))

(sqrt(2)(2+sqrt(3)))/(sqrt(3)(sqrt(3)+1))-(sqrt(2)(2-sqrt(3)))/(sqrt(3)(sqrt(3)-1))

The rationalisation factor of sqrt(3) is -sqrt(3) (b) (1)/(sqrt(3))(c)2sqrt(3)(d)-2sqrt(3)

(2+sqrt(3))/(2-sqrt(3))+(2-sqrt(3))/(2+sqrt(3))+(sqrt(3)+1)/(sqrt(3)-1)is

By how much does sqrt(12)+sqrt(18) exceed sqrt(3)+sqrt(2)?sqrt(2)-4sqrt(3)(b)sqrt(3)+2sqrt(2)(c)2(sqrt(3)-sqrt(2))(d)3(sqrt(3)-sqrt(2))

The value of (2 + sqrt(3))/(2- sqrt(3)) + (2- sqrt(3))/(2 + sqrt(3)) + ( sqrt(3) + 1)/(sqrt(3) -1) is

If sqrt(2) = 1.414, sqrt(3) = 1.732, sqrt(5) = 2.236 and sqrt(6) = 2.449 , find the value of (2+sqrt(3))/(2-sqrt(3)) +(2-sqrt(3))/(2+sqrt(3)) +(sqrt(3) -1)/(sqrt(3) +1)