`(10)^(24)xx(10)^(-21)=?` `3` b. `10` c. `100` d. `1000`

10% of 1000% of 100=?

1000^(12)-:10^(30)=? a.1000^(2)b.10c.100d.100^(2)e. None of these

(3)/(10)+(5)/(100)+(8)/(1000)=

(2.4xx10^(3))-:(8xx10^(-2))=?3xx10^(-5)b3xx10^(4)c.3xx10^(5)d.30

Convert the fractions into a decimal: a. (17)/(10) b. (239)/(100) c. (2103)/(100) d. (3001)/(1000)

(log)_(10)(10xx10^(2)xx10^(3)xx xx10^(9)) is 10b.20 c.45d.55

log_(10)log_(10)log_(10)backslash(10^(10^(10))) is equal to a.0b.1 c.10d.100

The following steps are involved in finding the value of 10 (1)/(3) xx 9(2)/(3) by using an appropriate indentity . Arrange them in sequential order . (A) (10)^(2) - ((1)/(3))^(2) = 100 - (1)/(9) (B) 10(1)/(3) xx 9(2)/(3) = (10 + (1)/(3)) (10 - (1)/(3)) (C) (10 + (1)/(3)) (10 - (1)/(3)) = (10)^(2) - ((1)/(3))^(2) [because (a + b) (a -b) = (a^(2) - b^(2))] (D) 100 - (1)/(9) = 99 + 1 - (1)/(9) = 99(8)/(9)