`(2. 4xx10^3)-:(8xx10^(-2))=?` `3xx10^(-5)` b. `3xx10^4` c. `3xx10^5` d. `30`

(2.4xx10^3)div(8xx10^2)= ?

0.5xx10^(-4)xx0.3xx10^(-3)xx10

For a reaction 2NO(g) + 2H_(2)(g) rarr N_(2)(g)+2H_(2)O(g) the following data were obtained: |{:(,[NO] (mol L^(-1)),[H_(2)] (mol L^(-1)),"Rate" (mol L^(-1) s^(-1))),(1.,5 xx 10^(-3),2.5 xx 10^(-3),3 xx 10^(-5)),(2.,15 xx 10^(-3),2.5 xx 10^(-3),9xx10^(-5)),(3.,15 xx 10^(-3),10 xx 10^(-3),3.6 xx 10^(-4)):}| (a) Calculating the order of reactions. (b) Find the rate constant. (c ) Find the initial rate if [NO] = [H_(2)] = 8.0 xx 10^(-3) M

Calculate the following a. (6.7 xx 10^(5)) xx (4.6 xx 10^(4)) b. (7.6 xx 10^(7)) xx (3.8 xx 10^(-4)) c. (6.8 xx 10^(-3)) xx (5.2 xx 10^(-4)) d. (6.7 xx 10^(5)) / (4.6 xx 10^(4)) e. (7.6 xx 10^(7)) / (3.8 xx 10^(-4)) f. (6.8 xx 10^(-3)) / (3.8 xx 10^(-4)) g. 7.65 xx 10^(2) + 2.72 xx 10^(3) h. 7.87 xx 10^(-4) - 2.61 xx 10^(-5)

Hardness of water is 200 ppm. The normality and molarity of CaCO_3 in the water is (a). 2xx10^(-6)(N,2xx10^(-6)M (b). 4xx10^(-2)N,2xx10^(-2)M (c). 4xx10^(-3)N,2xx10^(-3)M (d). 4xx10^(-1)N,2xx10^(-1)M

(32xx10^(-5))^(2)xx64-:(2^(16)xx10^(-4))=10^(7)a6b.10c.-8d.-6

From the following data answer the questions Reaction A+B rarr P {:([A]M,,[B]M,,Initially rate (M sec^(-1)),,,),(,,,,at 300K,at 400K,,),(2.5xx10^(-4),,3.0xx10^(-5),,5.0xx10^(-4),2.0xx10^(-3),,),(5.0xx10^(-4),,6.0xx10^(-5),,4.0xx10^(-3),,,),(1.0xx10^(-3),,6.0xx10^(-5),,1.6xx10^(-2),,,):} The value of rate constant at 300 K is (M^(-2)sec^(-1))