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Given that 10^0.48=x ,\ 10^(0.70)=y\ and...

Given that `10^0.48=x ,\ 10^(0.70)=y\ and\ x^z=y^2,` then the value of `z` is close to a. `1. 45` b. `1. 88` c. `3. 7` d. `2. 9`

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