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If x^(1//3)+y^(1//3)=z^(1//3), then {(x+...

If `x^(1//3)+y^(1//3)=z^(1//3)`, then `{(x+y-z)^3+27 x y z}` equals a. `0` b. `-1` c. `1` d. `27`

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