The exponential form of `sqrt(sqrt(2)xxsqrt(3))` is a. `6` b. `6^(1//2)` c. `6^(1//3)` d. `6^(1//4)`

The value of sqrt(6+sqrt(6+sqrt(6+)))......... is 4(b)3(c)-2(d)3.5

(3-sqrt(6))/(3+2sqrt(6))=a sqrt(6)-b

The following are the steps involved in finding the greatest among root(3)(2),root(6)(3) and sqrt(6) . Arrange them in sequential order. (A) The LCM of the denominators of the exponents is 6. (B) therefore root(6)(216) i.e., sqrt(6) is greatest. (C) root(3)(2)=2^(1//3), root(6)(3)=3^(1//6), sqrt(6)=6^(1//2) (D) 2^(1//3)=2^(2//6), 3^(1//6), 6^(1//2)=6^(3//6) (E) root(3)(2)=root(6)(4)root(6)(3)-root(6)(3),sqrt(6)=root(6)(216)

The amplitude of (1+i sqrt(3))/(sqrt(3)+i) is (pi)/(3) b.-(pi)/(6) c.(pi)/(3) d.(pi)/(6)

(sqrt(7)+sqrt(5))/(sqrt(5)) is equal to (a) 1 (b) 2(c)6-sqrt(35) (d) 6+sqrt(35)

The value of sqrt(6+2sqrt(3)+2sqrt(2)+2sqrt(6))-(1)/(sqrt(5-2sqrt(6))) is

(sqrt(24)+sqrt(216))/(sqrt(96))=?2sqrt(6)(b)2(c)6sqrt(2)(d)

The value of cos^(-1)sqrt((2)/(3))-cos^(-1)((sqrt(6)+1)/(2sqrt(3))) is equal to (A)(pi)/(3)(B)(pi)/(4)(C)(pi)/(2)(D)(pi)/(6)])

(sqrt(-2))(sqrt(-3)) is equal to sqrt(6)b.-sqrt(6)c.i sqrt(6)d* none of these

2(sqrt(2)+sqrt(6)) The fraction (2(sqrt(2)+sqrt(6)))/(3(sqrt(2+sqrt(3)))) is equal to (A) (2sqrt(2))/(3)( B) 1(C)(2sqrt(3))/(3)(D)(4)/(3)