Two identical blocks of weigth w are placed one on top of the other as shown in figure. The upper block is tied to the wall. The coefficient of static friction between B and ground is `mu` and friction between A and B is absent. When `F=mu w`force is applied on the lower block as shown. The tension in the string will be

A block on table shown in figure is just on the wedge of slipping. Find the coefficient of static friction between the block and table top.

Two blocks of masses m and 2 m are placed one over the other as shown in figure.The coefficient of friction between m and 2m is mu and between 2m and ground is (mu)/(3) . If a horizontal force F is applied on upper block and T is tension developed in string, then choose the incorrect alternative.

Two blocks of masses m and 2 m are placed one over the other as shown in figure.The coefficient of friction between m and 2m is mu and between 2m and ground is (mu)/(3) . If a horizontal force F is applied on upper block and T is tension developed in string, then choose the incorrect alternative.

Block B rests on a smooth surface .The coefficient of static friction between A and B is mu = 0.4 where F = 30 N then Acceleration of upper block is

Block B rests on a smooth surface .The coefficient of static friction between A and B is mu = 0.4 where F = 30 N then Acceleration of upper block is

Block B rests on a smooth surface .The coefficient of static friction between A and B is mu = 0.4 where F = 30 N then Acceleration of lower block is

The friction coefficient between the blocks is mu . If force F is applied on the lower block , analyse motion of two blocks.

Four block are arranged on a smooth horizontal surface as shown in figure .The masses of the blocks are given (see the fig ) The coefficient of static friction between the top and the bottom blocks is mu_(s) What is the maximum value of the horizontal force F applied to one of the bottom blocks as shown that makes all four block with the same acceleration ?