+5)^(4)quad " 6."(x+(1)/(x))^(x)+x^((1+(1)/(x)))

Expand using binomial theorem: (i) (1-2x)^(4) " " (ii) (x+2y)^(5) (iii) (x-(1)/(x))^(6) " "(iv) ((2x)/(3)=(3)/(2x))^(5) (v) (x^(2) +(2)/(x))^(6)" "(vi) (1+(1)/(x^(2)))^(4)

(x^(2)+(1)/(x^(2)))-4(x+(1)/(x))+6

If x+(1)/(x)=6, find :x^(4)+(1)/(x^(4))

(x^(2)+(1)/(x^(2))+2)+(x^(4)+(1)/(x^(4))+5)+(x^(6)+(1)/(x^(6))+8)+

If x+(1)/(x)=6, find x^(2)+(1)/(x^(2))( ii) x^(4)+(1)/(x^(4))

Add: (3x^(2) - (1)/(5)x + (7)/(3)) + ((-1)/(4)x^(2) + (1)/(3)x - (1)/(6)) + (-2x^(2) - (1)/(2)x + 5)

[1+(1)/(x+1)][1+(1)/(x+2)][1+(1)/(x+3)][1+(1)/(x+4)] is (x+5)/(x+1) (b) (x+1)/(x+5) (c) 1+(1)/(x+5) (d) (1)/(x+5)