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[(5ecan-1)/(sec4A-1)=ul(11)],[[" (a) "(t...

[(5ecan-1)/(sec4A-1)=ul(11)],[[" (a) "(tan2A)/(tan8A)," (b) "(tan8A)/(tan2A)," (c) "(cot theta A)/(cot2A)," (d) None "]]

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(sec8A-1)/(sec4A-1) is equal to (A) (tan2A)/(tan8A) (B) (tan8A)/(tan2A) (C) (cot8A)/(cot2A) (D) none of these

(sec8A-1)/(sec4A-1) is equal to (A) (tan2A)/(tan8A) (B) (tan8A)/(tan2A) (C) (cot8A)/(cot2A) (D) none of these

(sec 8 A-1)/( sec 4A-1)= ..................... A) (tan 2A)/( tan 8A) B) (tan 8A)/(tan 2A) C) (cot 8A)/(cot 2A) D) (tan 6A)/(tan 2A)

(sec8A-1)/(sec4A-1)=(tan 8A)/(tan2A)

Prove that (sec8A-1)/(sec4A-1)=(tan8A)/(tan2A)

Prove that (sec 8A-1)/(sec 4A-1)=(Tan8A)/(Tan2A)

( tan^(3) theta )/( 1+ tan^(2) theta )+ ( cot^(3) theta )/( 1+ cot^(2) theta )=

(1+tan^(2)theta)/(1+cot^(2)theta)=((1-tan theta)/(1-cot theta))^(2)

Prove that : (tan^(2)theta)/(1+tan^(2)theta)+(cot^(2)theta)/(1+cot^(2)theta)=1

Prove that : (tan^(2)theta)/(1+tan^(2)theta)+(cot^(2)theta)/(1+cot^(2)theta)=1