A small disc of radius `r` is cut out from a disc of radius `R`. The weight of the disc which now has a hole in it, is reduced to `(24)/(25)` of the original weight. If `R=x\ r`, what is the value of `x`? (a) 4 (b) 4.5 (c) 24 (d) 25 (e) None of these

From the circular disc of radius 4R two small discs of radius R are cut off. The centre of mass of the new structure will be at

A disc of radis R is cut out from a larger disc of radius 2R in such a way that the edge of the hole touches the edge of the disc. Locate the centre of mass of the residual disc.

A disc of radius r is cut from a larger disc of radius 4r in such a way that the edge of the hole touches the edge of the disc. The centre of mass of the residual disc will be a distance from centre of larger disc :-

A circular disc of radius (R)/(4) is cut from a uniform circular disc of radius R. The centre of cut portion is at a distance of (R)/(2) from the centre of the disc from which it is removed. Calculate the centre of mass of remaining portion of the disc.

From a circular disc of radius R , another disc of diameter R is removed. Locate c.m. of the remaining portion.

A circular disc of radius R is removed from a bigger circular dise of radius such that the circumferences of the discs coincide. The centre of mass of the new disc is alphaR from the centre of the bigger disc. The value of a is:

A uniform metal disck of radius R is taken and out of it a disc of diameter R is cut-off from the end. The center of mass of the remaining part will be

A circular disc of radius R is removed from a bigger circular disc of radius 2 R such that the circumferences of the discs coincide. The center of mass of new disc is alpha R from the center of the bigger disc. The value of alpha is