A circle is circumscribed around a square as shown in the figure. The area of one of the four shaded portions is equal to `4/7` . The radius of the circle is (FIGURE) `sqrt(2)` (b) `1/(sqrt(2))` (c) 2 (d) 3

In the adjoining figure,if the radius of each of the four outer circles is r, what is the radius of the inner circle? (FIGURE) (a) (2)/(sqrt(2)+1)r(b)(1)/(sqrt(2))r(c)(sqrt(2)-1)r(d)sqrt(2)backslash r

In the figure, O is the centre of the circle. anglePOQ=90^@ . The area of the shaded region is 126cm^2 . Find the radius of the circle.

The area of a square is equal to the area of a circle.The ratio between the side of the square and the radius of the circle is (a) sqrt(pi):1 (b) 1:sqrt(pi)(c)1:pi(d)pi:1

Using figure 8.2, the ratio of the area of the shaded portion to that of the whole figure is ______.

In the following figure, if PQ = R (P is the centre of the bigger circle) and the shaded area is equal to A, then the radius of the inner circle is equal to -

A circle is inscribed in a square of side 54cms and another circle circumscribes the same square.Then the ratio of circumferences of the bigger circle to the smaller circle is 1backslash sqrt(2) (b) sqrt(2)backslash:1(c)sqrt(3)backslash1 (d) None of these

The line 2x-y+1=0 is tangent to the circle at the point (2,5) and the center of the circle lies on x-2y=4. The radius of the circle is 3sqrt(5)(b)5sqrt(3)(c)2sqrt(5)(d)5sqrt(2)

ABCD is a square of unit area.A circle is tangent to two sides of ABCD and passes through exactly one of its vertices.The radius of the circle is 2-sqrt(2)( b ) sqrt(2)-11/2(d)(1)/(sqrt(2))