If the average velocity of `N_(2)` molecules is `0.3 ms^(-1) at 27^(@) C` , then the velocity of `0.6 ms^(-1)` will take place at

At 27°C, the average speed of N_(2) molecules is x ms^(-1) At 927°, the speed will be_______ x ms^(-1)

The average veloctiy of an ideal gas molecule at 27^(@)C is 0.3 m s^(-1) . The average velocity at 927^(@)C will be

The average veloctiy of an ideal gas molecule at 27^(@)C is 0.3 m s^(-1) . The average velocity at 927^(@)C will be

The average velocity of gas molecules is 400 ms^(-1) . Its r.m.s. velocity at the same temperature is

Calculate the average velocity of oxygen molecule at 27^@C .

A gas consists of 4 molecules with a velocity of 5ms^(-1),10 molecules with a velocity of 3ms^(-1) and 6 molecules with a velocity of 6ms^(-1) . Calculate their average velocity, root mean square velocity and most probable velocity.

The average velocity of nitrogen at 27^@C is 0.3ms^(-1) . At what temperature it will be 0.6 ms^(-1) ?

A gas consists of 5 molecules with a velocity of 5ms^(-1) , 10 molecules with a veclocity of 3ms^(-1) and 6 molecules with a velocity of 6ms^(-1) . The ratio of average velocity and rms velocity of the molecles is 9.5xx10^(-x) Where x is……….