Solve : `2.5t + 7.3 t = 21.6 -t`

Solve : (t + 2)/(3) + 1/(t + 1) = (t - 3)/(2) - (t - 1)/(6)

Solve : (4t)/(5) - (5)/(3) lt (t)/(4) + (3)/(2), t in Q

Solve : (3t-2)/4 - (2t+3)/3 = 2/3 - t

Solve the equation : (3t+1)/16-(2t-3)/7=(t+3)/8+(3t-1)/14

Each of the four particles move along an x axis. Their coordinates (in metres) as function of time (in seconds) are given by Particle 1 : x(t) = 3.5 - 2.7 t^3 Particle 2 : x(t) = 3.5 + 2.7 t^3 Particle 3 : x(t) = 3.5 + 2.7 t^2 Particle 4 : x(t) = 2.5 - 3.4t - 2.7 t^2 which of these particles is speeding up for t > 0?

Each of four particles moves along an x axis. Their coordinates (in meters) as function of time (in seconds) are given by Particle 1:x(t) =3.5 -2.7t^(3) Particle :2 x(t)=3.5+2.7 t^(3) particle 3: x(t) =3.5+2.7 t^(2) particle 4: x(t)=3.5-3.4 t -2.7 t^(2) Which of these particles have constant acceleration ?

solve the equation . (3 t - 2)/(4 ) - (2 t + 3)/(3) = 2/3 - t

Subtract : 3t ^(4) - 4t ^(3) + 2t ^(2) - 6t + 6 from - 4t ^(4) + 8t ^(3) - 4t ^(2) - 2t + 11