Home
Class 14
MATHS
30.9 xx 3000 - 10.1 xx 1100 + 8298 - 430...

`30.9 xx 3000 - 10.1 xx 1100 + 8298 - 4302 = ? `

A

80000

B

90000

C

105000

D

85000

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \(30.9 \times 3000 - 10.1 \times 1100 + 8298 - 4302\), we will follow these steps: ### Step 1: Approximate the numbers First, we will round the numbers to make the calculations easier: - \(30.9 \approx 31\) - \(3000\) remains \(3000\) - \(10.1 \approx 10\) - \(1100\) remains \(1100\) - \(8298\) remains \(8298\) - \(4302\) remains \(4302\) ### Step 2: Calculate the products Now we will calculate the products using the approximated values: - \(31 \times 3000 = 93000\) - \(10 \times 1100 = 11000\) ### Step 3: Substitute the values into the expression Now substitute these values back into the original expression: \[ 93000 - 11000 + 8298 - 4302 \] ### Step 4: Perform the subtraction and addition Now we will perform the operations step by step: 1. Calculate \(93000 - 11000\): \[ 93000 - 11000 = 82000 \] 2. Next, calculate \(8298 - 4302\): \[ 8298 - 4302 = 3996 \] 3. Finally, add the results: \[ 82000 + 3996 = 85996 \] ### Step 5: Approximate the final result Now, we will round \(85996\) to the nearest thousand: \[ 85996 \approx 86000 \] Thus, the approximate value of the expression is: \[ \boxed{86000} \]
Promotional Banner

Topper's Solved these Questions

  • APPROXIMATION

    ARIHANT SSC|Exercise Fast Track Practice|74 Videos

  • ALLIGATIONS

    ARIHANT SSC|Exercise EXERCISE|29 Videos

  • AREA AND PERIMETER

    ARIHANT SSC|Exercise FAST TRACK TECHENIQUES|133 Videos

Similar Questions

Explore conceptually related problems

3 xx 10000 + 7 xx 1000 + 9 xx 100 + 0 xx 10 + 4 is the same as

421 xx 0.9 + 130 xx 101 + 10000 = ?

39746 = 3 xx 10000 + 9 xx 1000 + 7 xx 100 + 4 xx 10 + 6

Write the numeral whose expanded form is given below: ( i ) 6 xx 10^(4)+3 xx 10^(3)+0 xx 10^(2)+7 xx 10^(1)+8 xx 10^(0) ( ii ) 9 xx 10^(6)+7 xx 10^(5)+0 xx 10^(4)+3 xx 10^(3)+2 xx 10^(2)+9 xx 10^(1)+6 xx 10^(0) ( iii ) 8 xx 10^(5)+6 xx 10^(4)+4 xx 10^(3)+2 xx 10^(2)+9 xx 10^(1)+6 xx 10^(0)

Assertion : The number 211.902 is expressed in expanded form as 2 xx 100 xx1 xx 10 xx 1 + 9 xx ( 1)/( 10) xx 2 xx ( 1)/( 100) . Reason : As we go from left to right, the multiplying factor becomes ( 1)/( 10) of the previous factor.

1/2xx 5/4 + 6/8 xx 10/9

When light of wavelength 248 nm falls on a metal of threshold energy 3.0 eV, the de-Broglie wavelength of emitted electrons is "_________"Å (Round off to the Nearest Integer). [Use : sqrt3 = 1.73 , h - 6.63 xx 10 ^(-34) Js m _(c ) = 9.1 xx 10 ^(-31) kg , c =3.0 xx 10 ^(8) ms ^(-1) ,1eV = 1. 6 xx 10 ^(-19))]

Find each of the following products: (a) 3 xx (-1) (b) (-1) xx 225 (c) (-21) xx (-30) (d) (-316) xx (-1) (e) (-15 xx 0 xx (-18) (f) (-12) xx (-11) xx (10) (g) 9 xx (-3) xx (-6) (h) (-18) xx (-5) xx (-4) (i) (-1) xx (-2) xx (-3) xx 4 (j) (-3) xx (-6) xx (-2) xx (-1)

If 4 xx 9 xx 3= 4 and 5 xx 3 xx 1=3 , then 9 xx 9 xx 7=?