Home
Class 14
MATHS
2508 + 15.02 + ? xx 11 = 200...

`2508 + 15.02 + ? xx 11 = 200`

A

a. 13

B

b. 8

C

c. 3

D

d. 4

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \( 2508 + 15.02 + ? \times 11 = 200 \), we will follow these steps: ### Step 1: Rearrange the equation We start by moving the unknown term (question mark) to the other side of the equation. This gives us: \[ 2508 + 15.02 + ? \times 11 = 200 \] Subtract \( 2508 \) and \( 15.02 \) from both sides: \[ ? \times 11 = 200 - 2508 - 15.02 \] ### Step 2: Calculate the right side Now, we need to calculate the right side: \[ 200 - 2508 - 15.02 = 200 - 2523.02 = -2323.02 \] So, we have: \[ ? \times 11 = -2323.02 \] ### Step 3: Isolate the question mark Next, we divide both sides by 11 to isolate the question mark: \[ ? = \frac{-2323.02}{11} \] ### Step 4: Perform the division Now, we perform the division: \[ ? = -211.18 \] ### Final Answer Thus, the value of the question mark is approximately: \[ ? \approx -211.18 \]
Promotional Banner

Topper's Solved these Questions

  • APPROXIMATION

    ARIHANT SSC|Exercise Fast Track Practice|74 Videos
  • ALLIGATIONS

    ARIHANT SSC|Exercise EXERCISE|29 Videos
  • AREA AND PERIMETER

    ARIHANT SSC|Exercise FAST TRACK TECHENIQUES|133 Videos

Similar Questions

Explore conceptually related problems

Find the value of 200 xx 20 xx 2 xx 0.2 xx 0.02xx 0.002= ? A. 0.064 B 0.64 C. 64 D 640

The dimensions of a class room are 15 ft xx 10 ft xx 11 ft. The area of four walls is ______.

5/11 xx 11/5

Find the value of frac((0.0112 - 0.0012) xx 0.14 + 0.025 xx 0.2 )(0.02 xx 0.01)

0.02xx30 = ?