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Population of a city in 2004 was 1000000...

Population of a city in 2004 was 1000000. If in 2005 there is an increment of 15%, in 2006 there is a decrement of 35% and in 2007 there is an increment of 45%,then find the population of city at the end of year 2007.

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To find the population of the city at the end of the year 2007, we will follow these steps: ### Step 1: Calculate the population for 2005 The population in 2004 is 1,000,000. There is a 15% increment in 2005. **Calculation:** - Increment = 15% of 1,000,000 - Increment = (15/100) * 1,000,000 = 150,000 **New Population in 2005:** - Population in 2005 = 1,000,000 + 150,000 = 1,150,000 ### Step 2: Calculate the population for 2006 The population in 2005 is 1,150,000. There is a 35% decrement in 2006. **Calculation:** - Decrement = 35% of 1,150,000 - Decrement = (35/100) * 1,150,000 = 402,500 **New Population in 2006:** - Population in 2006 = 1,150,000 - 402,500 = 747,500 ### Step 3: Calculate the population for 2007 The population in 2006 is 747,500. There is a 45% increment in 2007. **Calculation:** - Increment = 45% of 747,500 - Increment = (45/100) * 747,500 = 336,375 **New Population in 2007:** - Population in 2007 = 747,500 + 336,375 = 1,083,875 ### Final Answer: The population of the city at the end of the year 2007 is **1,083,875**. ---
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