The population of a town is 705600.If it increases at the rate of 5% per annum,then what will be its population 2yr hence?

Options

A. 777924
B. 777881
C. 778781
D. 797724

Answer

To solve the problem of finding the population of a town after 2 years given an initial population and a percentage increase, we can follow these steps:

### Step 1: Identify the initial population and the rate of increase
- The initial population of the town is 705600.
- The rate of increase is 5% per annum.

### Step 2: Calculate the population after the first year
- To find the population after the first year, we need to calculate 5% of the initial population and then add it to the initial population.

\[ \text{Increase after 1 year} = \text{Initial Population} \times \frac{5}{100} = 705600 \times 0.05 = 35280 \]

- Now, add this increase to the initial population:

\[ \text{Population after 1 year} = \text{Initial Population} + \text{Increase after 1 year} = 705600 + 35280 = 740880 \]

### Step 3: Calculate the population after the second year
- Now, we will use the population at the end of the first year as the new initial population for the second year.

\[ \text{Increase after 2 years} = \text{Population after 1 year} \times \frac{5}{100} = 740880 \times 0.05 = 37044 \]

- Add this increase to the population at the end of the first year:

\[ \text{Population after 2 years} = \text{Population after 1 year} + \text{Increase after 2 years} = 740880 + 37044 = 777924 \]

### Final Answer
- The population of the town after 2 years will be **777924**.

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