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If the numerator of a fraction is increa...

If the numerator of a fraction is increased by 200% and the denominator of the fraction is increased by 150%, the resultant fraction is `9/(35)` . What is the orginal fractional ?

A

`3/(10)`

B

`2/(15)`

C

`(3)/(14)`

D

`3/7`

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The correct Answer is:
To solve the problem step by step, we need to first understand the changes made to the numerator and denominator of the original fraction. 1. **Let the original fraction be \( \frac{x}{y} \)**, where \( x \) is the numerator and \( y \) is the denominator. 2. **Increase the numerator by 200%**: - Increasing by 200% means adding 2 times the original numerator to itself. - Therefore, the new numerator becomes: \[ x + 200\% \text{ of } x = x + 2x = 3x \] 3. **Increase the denominator by 150%**: - Increasing by 150% means adding 1.5 times the original denominator to itself. - Therefore, the new denominator becomes: \[ y + 150\% \text{ of } y = y + 1.5y = 2.5y \] 4. **Set up the equation with the resultant fraction**: - According to the problem, the resultant fraction after these increases is \( \frac{9}{35} \). Therefore, we can set up the equation: \[ \frac{3x}{2.5y} = \frac{9}{35} \] 5. **Cross-multiply to solve for \( x \) and \( y \)**: - Cross-multiplying gives us: \[ 3x \cdot 35 = 9 \cdot 2.5y \] - Simplifying this, we get: \[ 105x = 22.5y \] 6. **Rearranging the equation**: - We can express \( y \) in terms of \( x \): \[ y = \frac{105x}{22.5} \] - Simplifying \( \frac{105}{22.5} \): \[ y = \frac{1050}{225}x = \frac{14}{3}x \] 7. **Finding the original fraction**: - The original fraction \( \frac{x}{y} \) can now be expressed as: \[ \frac{x}{\frac{14}{3}x} = \frac{3}{14} \] Thus, the original fraction is \( \frac{3}{14} \).
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