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A jogger desires to run a certain course...

A jogger desires to run a certain course in `1/4` less time than he usually takes. But what per cent must be incresase his average running speed to accomplish the goal ?

A

`50%`

B

`20%`

C

`25%`

D

`33(1)/(3)` %

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how much the jogger must increase his average running speed to run a course in \( \frac{1}{4} \) less time, we can follow these steps: ### Step 1: Understand the relationship between speed, distance, and time The basic formula that relates speed (S), distance (D), and time (T) is: \[ D = S \times T \] This means that distance is equal to speed multiplied by time. ### Step 2: Define the variables Let: - \( T \) = original time taken to run the course - \( S \) = original speed - \( D \) = distance of the course From the formula, we can express the distance as: \[ D = S \times T \] ### Step 3: Calculate the new time The jogger wants to run the course in \( \frac{1}{4} \) less time. Therefore, the new time \( T' \) is: \[ T' = T - \frac{1}{4}T = \frac{3}{4}T \] ### Step 4: Calculate the new speed To cover the same distance \( D \) in the new time \( T' \), the new speed \( S' \) must be: \[ D = S' \times T' \] Substituting for \( T' \): \[ D = S' \times \frac{3}{4}T \] ### Step 5: Set the equations equal to each other Since the distance \( D \) remains constant, we can set the two equations for distance equal to each other: \[ S \times T = S' \times \frac{3}{4}T \] ### Step 6: Solve for the new speed Dividing both sides by \( T \) (assuming \( T \neq 0 \)): \[ S = S' \times \frac{3}{4} \] Rearranging gives: \[ S' = \frac{4}{3}S \] ### Step 7: Calculate the increase in speed The increase in speed is: \[ \text{Increase} = S' - S = \frac{4}{3}S - S = \left(\frac{4}{3} - 1\right)S = \frac{1}{3}S \] ### Step 8: Calculate the percentage increase To find the percentage increase in speed: \[ \text{Percentage Increase} = \left(\frac{\text{Increase}}{S}\right) \times 100 = \left(\frac{\frac{1}{3}S}{S}\right) \times 100 = \frac{1}{3} \times 100 = 33.33\% \] ### Final Answer The jogger must increase his average running speed by **33.33%** to accomplish his goal. ---
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