In an examination, it is required to get 296 marks out of aggregate marks to pass. A student gets 222 marks and is declared failed by 10% marks. What are the maximum aggregate marks a student can get?

Options

A. 830
B. 810
C. 780
D. 740

Answer

To solve the problem step by step, we will follow the information given in the question and derive the maximum aggregate marks.

### Step-by-Step Solution:

1. **Identify the Given Information:**
- Passing marks required = 296
- Marks scored by the student = 222
- Percentage by which the student failed = 10%

2. **Understand the Failure Condition:**
- The student failed by 10% of the maximum aggregate marks (let's denote it as M).
- This means that if the student had scored an additional 10% of M, he would have passed.

3. **Set Up the Equation:**
- According to the problem, the marks the student scored (222) plus the 10% of maximum aggregate marks (0.10 * M) equals the passing marks (296).
- We can write this as:
\[ 222 + 0.10M = 296 \]

4. **Isolate the Variable (M):**
- To find M, we first subtract 222 from both sides:
\[ 0.10M = 296 - 222 \]
- Calculate the right side:
\[ 0.10M = 74 \]

5. **Solve for M:**
- Now, divide both sides by 0.10 to find M:
\[ M = \frac{74}{0.10} \]
- Simplifying this gives:
\[ M = 740 \]

6. **Conclusion:**
- The maximum aggregate marks a student can get is **740**.

### Final Answer:
The maximum aggregate marks a student can get is **740**.

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