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A shopkeeper sells a transistors at 15% ...

A shopkeeper sells a transistors at 15% above its cost price. If he had bought it at 5% more than what he paid for it and sold it for 6 Rs. more, he would have gained 10%. The cost price of the transistor is

A

800

B

1000

C

1200

D

1400

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AI Generated Solution

The correct Answer is:
To solve the problem step by step, let's denote the cost price of the transistor as \( CP \). 1. **Selling Price Calculation**: The shopkeeper sells the transistor at 15% above its cost price. \[ SP = CP + 0.15 \times CP = 1.15 \times CP \] 2. **New Cost Price Calculation**: If the shopkeeper had bought it at 5% more than the original cost price, the new cost price would be: \[ New \, CP = CP + 0.05 \times CP = 1.05 \times CP \] 3. **New Selling Price Calculation**: If he sells it for Rs. 6 more than the original selling price, the new selling price would be: \[ New \, SP = SP + 6 = 1.15 \times CP + 6 \] 4. **Profit Calculation**: According to the problem, if he sold it at this new selling price, he would gain 10%. Therefore, the new selling price can also be expressed as: \[ New \, SP = New \, CP + 0.10 \times New \, CP = 1.10 \times New \, CP \] 5. **Setting Up the Equation**: We can set the two expressions for the new selling price equal to each other: \[ 1.15 \times CP + 6 = 1.10 \times (1.05 \times CP) \] 6. **Expanding and Simplifying**: Expanding the right side: \[ 1.15 \times CP + 6 = 1.155 \times CP \] Now, rearranging the equation: \[ 6 = 1.155 \times CP - 1.15 \times CP \] \[ 6 = 0.005 \times CP \] 7. **Solving for CP**: Now, we can solve for \( CP \): \[ CP = \frac{6}{0.005} = 1200 \] Thus, the cost price of the transistor is \( \text{Rs. } 1200 \).
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