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What sum of money at compound interest w...

What sum of money at compound interest will amount to ? 4499.04 in 3 yr, if the rate of interest is 3% for the 1st yr, 4% for the 2nd yr and 5% for the 3rd yr ?

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To find the principal amount (the sum of money) that will amount to ₹4499.04 in 3 years with varying interest rates, we can use the formula for compound interest. The formula for the amount \( A \) after \( n \) years is given by: \[ A = P(1 + r_1)(1 + r_2)(1 + r_3) \] Where: - \( A \) is the amount after \( n \) years (₹4499.04 in this case) - \( P \) is the principal amount (the sum we want to find) - \( r_1, r_2, r_3 \) are the rates of interest for each year expressed as decimals. ### Step-by-Step Solution: 1. **Identify the interest rates for each year:** - For the 1st year, the interest rate \( r_1 = 3\% = 0.03 \) - For the 2nd year, the interest rate \( r_2 = 4\% = 0.04 \) - For the 3rd year, the interest rate \( r_3 = 5\% = 0.05 \) 2. **Set up the equation using the compound interest formula:** \[ 4499.04 = P(1 + 0.03)(1 + 0.04)(1 + 0.05) \] 3. **Calculate the factors:** - \( 1 + 0.03 = 1.03 \) - \( 1 + 0.04 = 1.04 \) - \( 1 + 0.05 = 1.05 \) 4. **Multiply the factors together:** \[ 1.03 \times 1.04 \times 1.05 \] First, calculate \( 1.03 \times 1.04 \): \[ 1.03 \times 1.04 = 1.0712 \] Now multiply this result by \( 1.05 \): \[ 1.0712 \times 1.05 = 1.12476 \] 5. **Substitute back into the equation:** \[ 4499.04 = P \times 1.12476 \] 6. **Solve for \( P \):** \[ P = \frac{4499.04}{1.12476} \] Now perform the division: \[ P \approx 3999.00 \] ### Final Answer: The sum of money (the principal amount) that will amount to ₹4499.04 in 3 years is approximately ₹3999.00. ---
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