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Find the compound interest on X 31250 at...

Find the compound interest on X 31250 at 16% pa compounded quarterly for 9 months.

A

X 4000

B

X 3902

C

X 3500

D

X4200

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The correct Answer is:
To find the compound interest on ₹31,250 at an interest rate of 16% per annum compounded quarterly for 9 months, we can follow these steps: ### Step 1: Identify the given values - Principal (P) = ₹31,250 - Annual Interest Rate (R) = 16% - Time (T) = 9 months ### Step 2: Convert the annual interest rate to a quarterly interest rate Since the interest is compounded quarterly, we need to divide the annual interest rate by 4: \[ \text{Quarterly Rate} = \frac{R}{4} = \frac{16\%}{4} = 4\% \] ### Step 3: Convert the time period from months to quarters Since the interest is compounded quarterly, we need to convert the time period from months to quarters: \[ \text{Time in years} = \frac{9 \text{ months}}{12} = \frac{3}{4} \text{ years} \] To convert this to quarters: \[ \text{Time in quarters} = \frac{9 \text{ months}}{3 \text{ months/quarter}} = 3 \text{ quarters} \] ### Step 4: Use the compound interest formula The formula for compound interest is: \[ A = P \left(1 + \frac{r}{100}\right)^n \] Where: - \( A \) = Amount after time \( n \) - \( P \) = Principal - \( r \) = Rate of interest per period - \( n \) = Number of periods Substituting the values: \[ A = 31250 \left(1 + \frac{4}{100}\right)^3 \] \[ A = 31250 \left(1 + 0.04\right)^3 \] \[ A = 31250 \left(1.04\right)^3 \] ### Step 5: Calculate \( (1.04)^3 \) Calculating \( (1.04)^3 \): \[ (1.04)^3 = 1.124864 \] ### Step 6: Calculate the total amount \( A \) Now substitute back to find \( A \): \[ A = 31250 \times 1.124864 \approx 35152.00 \] ### Step 7: Calculate the compound interest The compound interest (CI) can be calculated as: \[ CI = A - P \] Substituting the values: \[ CI = 35152.00 - 31250 = 3902.00 \] ### Final Answer The compound interest on ₹31,250 at 16% per annum compounded quarterly for 9 months is approximately ₹3,902.00. ---
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