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A boat has to travel upstream 20 km dist...

A boat has to travel upstream 20 km distance from point X of a river to point Y. The total time taken by boat in travelling from point X to Y and Y to X is 41 min 40 s. What is the speed of the boat?

A

a. 66 km/h

B

b. 72 km/h

C

c. 48 km/h

D

d. Cannot be determined

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to analyze the situation involving the boat traveling upstream and downstream in a river. ### Step 1: Understand the problem The boat travels a distance of 20 km upstream from point X to point Y and then returns downstream from Y to X. The total time taken for this round trip is 41 minutes and 40 seconds. ### Step 2: Convert the total time into hours Since speed is usually expressed in km/h, we need to convert the total time taken into hours. - Total time = 41 minutes and 40 seconds - Convert minutes to hours: \[ 41 \text{ minutes} = \frac{41}{60} \text{ hours} \approx 0.6833 \text{ hours} \] - Convert seconds to hours: \[ 40 \text{ seconds} = \frac{40}{3600} \text{ hours} \approx 0.0111 \text{ hours} \] - Total time in hours: \[ \text{Total time} = 0.6833 + 0.0111 \approx 0.6944 \text{ hours} \] ### Step 3: Set up the equations for speed Let: - \( A \) = speed of the boat in still water (km/h) - \( B \) = speed of the river current (km/h) When the boat travels upstream (against the current), its effective speed is \( A - B \). When it travels downstream (with the current), its effective speed is \( A + B \). ### Step 4: Write the time equations The time taken to travel upstream (20 km) is: \[ \text{Time upstream} = \frac{20}{A - B} \] The time taken to travel downstream (20 km) is: \[ \text{Time downstream} = \frac{20}{A + B} \] The total time for the round trip is: \[ \frac{20}{A - B} + \frac{20}{A + B} = 0.6944 \] ### Step 5: Simplify the equation Multiply through by \( (A - B)(A + B) \) to eliminate the denominators: \[ 20(A + B) + 20(A - B) = 0.6944(A^2 - B^2) \] This simplifies to: \[ 40A = 0.6944(A^2 - B^2) \] ### Step 6: Rearranging the equation Rearranging gives us: \[ 0.6944A^2 - 40A - 0.6944B^2 = 0 \] ### Step 7: Analyze the equation This is a quadratic equation in terms of \( A \). However, we have two unknowns \( A \) and \( B \) and only one equation, which means we cannot uniquely determine \( A \) without additional information about \( B \). ### Conclusion Since we cannot determine the speed of the boat without knowing the speed of the river, the problem does not have a unique solution.
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ARIHANT SSC-BOATS AND STREAMS -EXERCISE BASE LEVEL QUESTIONS
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  2. A man can row against the current three-fourth of a kilometre in 15 mi...

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  3. The speed of the current is 5 km/h. A motorboat goes 10 km upstream an...

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  4. A man can row 6km/h in still water. If the speed of the current is 2km...

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  5. A boat goes 48 km downstream in 20 h.It takes 4 h more to cover the sa...

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  6. Pawan can row 24 km/h in still water . When the river is running at 4....

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  7. Sameer can row a certain distance downstream in 24 h and can come back...

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  8. A sailor sails a distance of 48 km along the flow of a river in 8 h.If...

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  9. Speed of a motorboat in still water is 45 km./hr. If it takes 1 hour 2...

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  10. A boat has to travel upstream 20 km distance from point X of a river t...

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  11. A boat covers a distance of 30 km downstream in 2 h while it takes 6 h...

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  12. A boat's speed in still water is 5 km/h. While river is flowing with a...

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  13. A boat takes 9 h to travel a distance upstream and takes 3 h to travel...

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  14. A boat running upstream covers a distance of 10 km in 30 min and while...

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  15. A man can row at 10 km/h in still water. If he takes total 5 h to go t...

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  16. A steamer goes down stream from one port to another in 4 h.It covers t...

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  17. A man can row 7.5 km/h in still water. If the river is running at 1.5 ...

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  18. Ashutosh can row 24 km/h in still water . It takes him twice as long t...

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  19. A boat goes 12 km in 1 h in still water. It takes thrice time in cover...

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  20. A boatman takes twice as long to row a distance against the stream as ...

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