A small mass slides down an inclined plane of inclination `theta` the horizontal the coefficient of friction is `m = mu_(0)x`, where x is the distance by the mass before it stops is .

A small mass slides down an inclined plane of inclination theta with the horizontal the coefficient of friction is mu = mu_(0)x , where x is the distance through which the mass slides down. Then the distance covered by the mass before it stops is

A small mass slides down an inclined plane of inclination theta with the horizontal. The co-efficient of friction is mu=mu_(0) x where x is the distance through which the mass slides down and mu_(0) a constant. Then, the distance covered by the mass before it stops is

A small mass slides down an inclined plane of inclination theta with the horizontal. The co-efficient of friction is mu=mu_(0) x where x is the distance through which the mass slides down and mu_(0) a constant. Then, the distance covered by the mass before it stops is

A small mass slide down an inclined plane of inclination theta with the horizontal. The coefficent of friction is mu=mu_(0) x where x is the distance through which the mass slide down and mu_(0),a contant. Then the speed is maxmum after the mass covers a distance of.

When a body of mass M slides down an inclined plane of inclination theta , having coefficient of friction mu through a distance s, the work done against friction is :

When a body of mass M slides down an inclined plane of inclination theta , having coefficient of friction mu through a distance s, the work done against friction is :

A block of mass m slides down a rough inclined plane of inclination theta with horizontal with zero initial velocity. The coefficient of friction between the block and the plane is mu with theta gt tan^(-1)(mu) . Rate of work done by the force of friction at time t is