A physical quantity A is related to four observable a,b,c and d as follows, `A=(a^2b^3)/(csqrtd)`, the percentage errors of measurement is a,b,c and d,are `1%`,`3%`,`2%` and `2%` respectively. What is the percentage error in the quantity A?

A physical quantity A is related to four observable a,b,c and d as follows, A=(a^2b^3)/(dsqrtc) , the percentage errors of measurement is a,b,c and d,are 1% , 3% , 2% and 1% respectively. What is the percentage error in the quantity A?

A physical quantity P is related to four observables a, b, c and d as follows :- P=a^3b^2//((sqrtc)d) The percentage errors of measurement in a, b, c and d are 1%, 3%, 4% and 2%, respectively. What is the percentage error in the quantity P? If the value of Pcalculated using the above relation turns out to be 3.763, to what value should you round off the result ?

A Physical quantity P is related to four observables a,b,c and d as follows: P=(a^3b^2)/(sqrtc d) The percentage errors of measurement in a,b,c and d are 1% , 3% , 4% and 2% respectively. What is the percentage error in the quantity P? If the value of P calculated using the above relation turns out to be 3.763 , to what value should you round off the result?

A physical quantity P is related to four observables a,b,c and d as follows: P = a^(3)b^(2)/(sqrtcd) The percentage errors of measurement in a,b, c and d are 1%, 3% , 4% and 2% respectively. What is the percentage error in the quantity P ? If the value of P calculated using the above relation turns out to be 3.763, to what value should you round off the result ?

A physical quantity P is related to four observables a,b,c and d as follows: P = a^(3)b^(2)/(sqrtcd) The percentage errors of measurement in a,b, c and d are 1%, 3% , 4% and 2% respectively. What is the percentage error in the quantity P ? If the value of P calculated using the above relation turns out to be 3.763, to what value should you round off the result ?