In a triangle ABC ,if the centroid is (2,0) and the mid point of BC is (1,3) then A=

In Delta ABC,A(5,6) and its centroid is (2,3) then mid point of the side BC is

If vertex A of triangle ABC is (3,5) and centroid is (-1,2) , then find the midpoint of side BC.

Suppose z_(1), z_(2), z_(3) represent the vertices A, B and C respectively of a Delta ABC with centroid at G. If the mid point of AG is the origin, then

In Delta ABC if the orthocentre is (1,2) and the circumcenter is (0,0) then centroid of Delta ABC is.

If the circumcentre of a triangle lies at the point (a, a) and the centroid is the mid - point of the line joining the points (2a+3, a+4) and (a-4, 2a-3) , then the orthocentre of the triangle lies on the line

In a triangle ABC,D and E are the mid- points of BC,CA respectively.If AD=5,BC=BE=4, then CA=

In Delta ABC if r_(1)=2r_(2)=3r_(3) and D is the mid point of BC then cos/_ADC=