In a `triangle ABC` the sides `BC=5, CA=4` and `AB=3`. If `A(0,0)` and the internal bisector of angle A meets BC in D `(12/7,12/7)` then incenter of `triangle ABC` is

In a /_ABC the sides BC=5,CA=4 and AB=3. If A(0,0) and the internal bisector of angle A meets BC in D((12)/(7),(12)/(7)) then incenter of /_ABC is

In a Delta ABC,AD is the bisector of the angle A meeting BC at D.If I is the in centre of the triangle,then AI:DI is equal to

Prove that the internal bisector of the angle A of a triangle ABC divides BC in the ratio AB:AC

In a triangle ABC, D is a point on BC such that AD is the internal bisector of angle A . Let angle B = 2 angle C and CD = AB. Then angle A is

ABC is a right triangle with AB = AC.If bisector of angle A meet BC at D then prove that BC =2 AD .

Given a triangle ABC with AB=2 and AC=1. Internal bisector of /_BAC intersects BC at D. If AD=BD and Delta is the area of triangle ABC, then find the value of 12Delta^(2).