Particle of mass 0.2kg is moving in a circle of radius 2m with frequency `(2)/(pi)s^(-1)` then its angular momentum is

A particle of mass 0.2 kg is moving in a circle of radius 1 m with f=(2//pi)sec^(-1) , then its angular momentum is :

A particle of mass 1kg is moving about a circle of radius 1m with a speed of 1m//s . Calculate the angular momentum of the particle.

If a particle of mass 1 gm is moving along a circular path of radius 1 m with a velocity of 1 m/s, then the its angular momentum is

A stone of mass 1 kg is rotated in a horizontal circle of radius 0.5 m. If it makes (100)/(pi) r.p.s. then its angular momentum is

Centripetal acceleration of a particle of mass m moving in a circle of radius r is 4//r^(2) . What is the angular momentum of the particle ?

A particle of mass m is moving along a circle of radius r with a time period T . Its angular momentum is

A particle of mass 0.5kg is rotating in a circular path of radius 2m and centripetal force on it is 9 Newtons Its angular momentum (in J-sec)

IF a particle of mass m is moving in a horizontal circle of radius r with a centripetal force (-(K)/(r^(2))) , then its total energy is

A particle of mass 0.5kg is rotating in a circular path of radius 2m and centripetal force on it is 9 Newtons. Its angular momentum (in J-sec) is:

If a particle of mass m is moving in a horizontal circle of radius r with a centripetal force (-1//r^(2)) , the total energy is