If `a b+b c+c a=0,` then solve `a(b-2c)x^2+b(c-2a)x+c(a-2b)=0.`

If ab+bc+ca=0, then solve a(b-2c)x^(2)+b(c-2a)x+c(a-2b)=0

If a , b , c are positive numbers such that a gt b gt c and the equation (a+b-2c)x^(2)+(b+c-2a)x+(c+a-2b)=0 has a root in the interval (-1,0) , then

If a , b , c are positive numbers such that a gt b gt c and the equation (a+b-2c)x^(2)+(b+c-2a)x+(c+a-2b)=0 has a root in the interval (-1,0) , then

If a , b , c are positive numbers such that a gt b gt c and the equation (a+b-2c)x^(2)+(b+c-2a)x+(c+a-2b)=0 has a root in the interval (-1,0) , then

If a , b , c are positive numbers such that a gt b gt c and the equation (a+b-2c)x^(2)+(b+c-2a)x+(c+a-2b)=0 has a root in the interval (-1,0) , then

If a, b, c are in H.P., then the equation a(b-c) x^(2) + b(c-a)x+c(a-b)=0