`tan(A+B)tan(A-B)`= ___________.

Prove that, tan (B - C) + tan (C -A ) + tan (A -B) = tan (B-C) tan (C-A) tan (A -B)

If tan (A+B)=p, tan(A-B)=q find tan 2A.

If tan(A+B)=m , tan (A-B)=n, " then " tan 2A=

If tan(A+B)=p&tan(A-B)=q , then the value of tan 2A is

If tan(A+B)=pand tan(A-B)=q, then the value of tan2A, is

If tan(A+B)=pand tan(A-B)=q, then the value of tan2A, is

(tan A + tan B) / (tan (A + B)) + (tan A-tan B) / (tan (AB)) =

In a triangle ABC , right angled at A ,the altitude through A and internal bisector of /_A have lengths 3 and 4 respectively. Find the length of median through A. Given that tan(A+B)=(tan A+tan B)/(1-tan A tan B),tan(A-B)=(tan A-tan B)/(1+tan A tan B)

In a triangle ABC ,right angled at A ,the altitude through A and internal bisector of /_A have lengths 3 and 4 respectively. Find the length of median through A . (Given that tan(A+B)=(tan A+tan B)/(1-tan A tan B),tan(A-B)=(tan A-tan B)/(1+tan A*tan B))

If tan (x-A)tan (x-B)+tan (x-B)tan (x-C)+tan(x-C)tan (x-A)=1 and A,B and C are the angles of triangle ABC then find x