A force of `5 N` acts on a particle along a direction making an angle of `60^(@)` with verticle. Its verticel components is

A force of 5N acts on a particle along a direction making an angle of 30^(@) with vertical . Its vertical component will be :

A force of 5N acts on a particle along a direction making an angle of 30^(@) with vertical . Its vertical component will be :

A force of 10.5 N acts on a particle along a direction making an angle of 37^0 with the vertical. Find the component of the force in the vertical direction.

A force of 10.5 N acts on a particle along a direction making an angle of 37^0 with the vertical. Find the component of the force in the vertical direction.

A body, acted upon by a force of 50N, is displaced through a distance 10m in direction making an angle of 60^(@) with the force. Find the work done by the force.

A body, acted upon by a force of 50N, is displaced through a distance 10m in direction making an angle of 60^(@) with the force. Find the work done by the force.

A body acted upon by a force of 50N is displaced through a distance of 10m in a direction making an angle of 60^(@) with the force. Calculate the work done by the force.

A body of mass 5 kg is placed at the origin, and can move only on the x-axis. A force of 10 N is acting on it in a direction making an angle of o 60^(@) with the x-axis and isplaces it along the x-axis by 4 metres . The work done by the force is