In displacement method, the distance between object and screen is 96 cm. The ratio of length of two images formed by a convex lens placed between them is 4.84.

In displacement method, the distance between object and screen is 96cm. The ratio of lengths of two images formed by a converging lens placed between them is 4. Then,

In displacement method, the distance between object and screen is 96cm. The ratio of lengths of two images formed by a converging lens placed between them is 4. Then,

In a displacement method the distance between the object and the screen is 70 cm and the focal length of the lens is 16 cm, find the separations of the magnified and diminished image position of the lens.

In the displacement method the distance between the object and the screen is 70 cm and the focal length of the lens is 16 cm, find the seperation of the magnified and diminished image position of the lens.

In a displacement method the distance between the object and the screen is 70 cm and the focal length of the lens is 16 cm, find the separations of the magnified and diminished image position of the lens.

In a displacement method the distance between the object and the screen is 70 cm and the focal length of the lens is 16 cm, find the separations of the magnified and diminished image position of the lens.

In displacement method distance of object and screen is 100 cm initial image is obtained on screen. Now lens is displaced 40 cm image formed on screen again . If power of the lens is (100/N) dioptre, then find the value of N :

In displacement method distance of object and screen is 100 cm initial image is obtained on screen. Now lens is displaced 40 cm image formed on screen again . If power of the lens is (100/N) dioptre, then find the value of N :

Show that the minimum distance between the object and the screen is 4 times of focal length of a convex lens at the time of real image formation.