A man directly crosses a river in time `t_1` and swims down the current a distance equal to the width of the river I time `t_2`. If `u and v` be the speed of the current and the man respectively, show that : `t_1 :t_2 = sqrt(v + u) : sqrt(v - u))`.

Rate of current when man go across the width of river in t and t hours.

A man wishes to cross a river flowing with velocity u swims at an angle theta with the river flow.If the man swims with speed v and if the width of the river is d , then the drift travelled by him is

A man rows across a flowing river in time t_(1) and rows an equal distance downstream in time t_(2) . Calculate the ratio t_(1):t_(2) if the speed of man in still water is 5 m//s and speed of stream is 3m//s .

A man swims across a river with speed of V_(m) perpendicular to the flow direction of river. If the water flows with a speed V_(w) with what resullant velocity does the man cross the river ?

The width of a river is D. A man can cross the river in time t_1 in the absence of any river current. But in presence of a certain river current, the man takes a time t_2 to cross the river directly. Show that the velocity of the current is v=D sqrt((1)/(t_1^2)-(1)/(t_2^2))

A man crosses the river perpendicular to river in time t seconds and travels an equal distance down the stream in T seconds. The ratio of man's speed in still water to the river water will be:

A man crosses the river perpendicular to river in time t seconds and travels an equal distance down the stream in T seconds. The ratio of man's speed in still water to the river water will be:

A man wants to swim in a river from A to B and back from B to A always following line AB (Fig. 5.94). The distance between points A and B is S . The velocity of the river current v is constant over the entire width of the river. The line AB makes an angle prop with the direction of current. The man moves with velocity u at angle beta to the line AB . The man swim to cover distance AB and back, find the time taken to complete the journey. .