Home
Class 12
MATHS
Given ABCD is a parallelogram wilth vert...

Given `ABCD` is a parallelogram wilth vertices as `A(1,2),B(3,4)` and `C(2,3)`. Then the equation of line `AD` is (A) `x+y+1=0` (B) `x-y+1=0` (C) `-x+y+1=0` (D) `x+y-1=0`

Promotional Banner

Similar Questions

Explore conceptually related problems

Given ABCD is a parallelogram with vertices as A(1,2),B(3,4) and C(2,3) . Then the equation of line AD is (A) x+y+1=0 (B) x-y+1=0 (C) -x+y+1=0 (D) x+y-1=0

The vertices of a parallelogram in order are A(1,2), B (4,y), C (x,6) and D(3,5) . Then (x,y) is :

The vertices of a parallelogram in order are A(1,2), B(4, y), C(x, 6) and D(3,5). Then (x, y) is

The vertices of a parallelogram in order are A(1, 2), B(4, y), C(x, 6), D(3, 5), then (x, y) =

The equation of tangent to the curve y= x^2 +4x+ 1 at (-1, 1) is...... A) 2x-y+3=0 B) 2x+y-5=0 C) 2x-y-1 =0 D) x+y-1 =0

The normal at the point (1,1) on the curve 2y+x^2=3 is (A) x - y = 0 (B) x y = 0 (C) x + y +1 = 0 (D) x y = 0

The normal at the point (1,1) on the curve 2y+x^2=3 is (A) x + y = 0 (B) x y = 0 (C) x + y +1 = 0 (D) x y = 0

If (2, -2),(-1,2), (3,5) are the vertices of a triangle then the equation of the side not passing through (2,-2) is (A) x + 2y +1 = 0 (B) 2x - y- 4= 0 (C) X-3y -3= 0 (D) 3x – 4y + 11 = 0

The equation of tangent y= x^2 +4x+1 at (-1, 2) is………. A) 2x -y+4=0 B) 2x+y-5=0 C) 2x+y-1=0 D) x+y-1=0

The equation of the tangent to the curve y=sec x at the point (0,1) is (a) y=0 (b) x=0 (c) y=1 (d) x=1