In the adjoining figure, AD is a median of `DeltaABC.` If BL and CM are drawn perpendiculars on AD and AD produced, prove that BL = CM.

In the fig. AD is a median of triangleABC . If BL and CM are drawn perpendicular on AD and AD produced, prove that BL=CM

In the adjoining figure, D is the mid-point of BC. If BM and CN are perpendiculars from B and C respectively on AD and AD produced, then prove that BM = CN.

In the adjoining figure, D is the mid-point of BC. If BM and CN are perpendiculars from B and C respectively on AD and AD produced, then prove that BM = CN.

In Figure,AD is a median and BL,CM are perpendiculars drawn from B and C respectively on AD and AD produced.Prove that BL=CM

In Figure,AD is a median and BL,CM are perpendiculars drawn from B and C respectively on AD and AD produced.Prove that BL=CM. Figure

In the adjoining figure, AD is the median of Delta ABC and X be any point on side AD. Prove that: area (Delta ABX) = " area " (Delta ACX)

In the adjoining figure, AD is the median of Delta ABC and X be any point on side AD. Prove that: area (Delta ABX) = " area " (Delta ACX)

In the adjoining figure. AD and BE are two medians of DeltaABC. IfDF"||"BE,"then prove that"CF=1/4AC.

In the following figure, AD and CE are medians of DeltaABC . DF is drawn parallel to CE. Prove that : EF = FB

In the given figure, AD is median of DeltaABC and E is any point on median AD. Prove that Area (DeltaABE) = Area (DeltaACE)