" (d) "int1cosec^(2)axdx

int cosec^(2)xdx

int x cos ec^(2)axdx

int cosec^(-1)xdx

int"cosec"^(2)(2x+5)dx

int(cosec^2(logx))/xdx

int cosec^2x cotxdx

int(cosec^2(logx))/xdx

We can derive different reduction formulas by using integration by parts. If int cosec^(n)x dx=(-cosec^(n-2)x cotx)/(n-1)+A int cosec^(n-2)x dx , then A is equal to-

int cotx cosec^(2)xdx

Evaluate : (i) int(sinx)/((1-4cos^(2)x))dx (ii) int("cosec"^(2)x)/((1-cot^(2)x))dx