[N_(2)+3H_(2)longrightarrow2NH_(3)" ,molecular weight of "NH_(3)],[" and "N_(2)" are "X," and "X_(2)" ,their equivalent weight are "Y_(1)],[" and "Y_(2)" ,then "(Y_(1)-Y_(2))" is "]

Consider the following reaction , N_(2) + 3H_(2) to 2NH_(3) Molecular weight of NH_(3) and N_2 are x_(1)" and "x_(2) respectively. Their equivalent weights are y_(1)" and "y_(2) respectively. Then (y_(1)-y_(2)) is

For the reaction, N_(2)(g)+3H_(2)(g)to 2NH_(3)(g) , if molecular masses of NH_(3) " and " N_(2) " and " M_(1) " and" M_(2) , their equivalent masses are E_(1) " and" E_(2) , then (E_(1)-E_(2)) is :

N_(2) + 3 H_(2) rarr 2NH_(3) Molecular weight of NH_(3) and N_(2) and x_(1) and x_(2) , respectively. Their equivalent weights are y_(1) and y_(2) , respectively. Then (y_(1) - y_(2))

N_(2) + 3 H_(2) rarr 2NH_(3) Molecular weight of NH_(3) and N_(2) and x_(1) and x_(2) , respectively. Their equivalent weights are y_(1) and y_(2) , respectively. Then (y_(1) - y_(2))

N_2+3H_2rarr2NH_3 Molecular weight of NH_3 and N_2 are X, and X_2 , their equivalent masses are _Y1 and Y_2 . Then (Y_1-Y_2) is

N_(2) + 3H_(2) to 2NH_(3) In this reaction, equivalent weight of N_(2) is :

N_(2) + 3H_(2) to 2NH_(3) In this reaction, equivalent weight of N_(2) is :