(2e^(2)+32e)^(2)-5(x^(2)+32e)-y(u^(2)+32)+5y

32^(2/5)

An ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 passes through the point (-3,1) and its eccentricity is sqrt((2)/(5)) The equation of the ellipse is 3x^(2)+5y^(2)=32 (b) 3x^(2)+5y^(2)=485x^(2)+3y^(2)=32(d)5x^(2)+3y^(2)=48

e_(1) and e_(2) are eccentricities of conies 5x^(2) + 9y^(2) = 45 and 5x^(2) - 4y^(2) = 45 then e_(1) .e_(2) = ……….

Solve for (x - 1)^(2) and (y + 3)^(2) , 2x^(2) - 5y^(2) - x - 27y - 26 = 3(x + y + 5) and 4x^(2) - 3y^(2) - 2xy + 2x - 32y - 16 = (x - y + 4)^(2) .

The curves 4x^(2) + 9y^(2) = 72 and x^(2) - y^(2) = 5 at (3,2)

Divide 14x^(3)y^(2)+8x^(2)y^(3)-32x^(2)y^(5) by -2xy^(2)

The solution of the differential equation log((dy)/(dx))=4x-2y-2,y=1 when x=1, is (A)2e^(2y+2)=e^(4x)+e^(2)(B)2e^(2y-2)=e^(4x)+e^(2)(C)2e^(2y+2)=e^(4x)+e^(4)(D)3e^(2y+2)=e^(3x)+e^(4)(C)2e^(2y+2)=e^(4x)+e^(4)(D)

If y= 3e^(2x)+ 2e^(3x) ,then (d^(2)y)/(dx^(2))-5(dy)/(dx) =