" 2) "x=sin sqrt(t),y=e^(sqrt(t))

x=sinsqrt(t),y=e^(sqrt(t)) find dy/dx

If x= sin sqrtt,y =e^(sqrt( t) ),then (d^(2)y)/(dx^(2))=

x=sqrt(sin 2t),y=sqrt(cos 2 t)

The slopee of normal to the curve x=sqrt(t) and y=t-(1)/(sqrt(t)) at t=4 is . . .

Find ( d^2 y)/(d x^2 ) of the following: x= sin sqrt t , y= sin sqrt t

Differentiate w.r.t. time. (i) y=t^(2) " " (ii) x=t^(3//2)" " (iii) y=(1)/(sqrt(t)) (iv) x=4t^(3) " " (v) y=2sqrt(t) " " (vi) y=2t^(2)+t-1 (vii) y=3sqrt(t)+(2)/(sqrt(t)) (viii) y=t^(3)sin t " " (ix) x=te^(t) (x) x= sqrt(t)(1-t)