[f:N rarr N" where "f(x)=x-(-1)^(x)" then "f" is "],[[" 1) one-one and into "," 2) many one-into "],[" 3) one-one and onto "," 4) many one and onto "]]

f: N rarr N, where f(x)=x-(-1)^(x) .Then f is: (a)one-one and into (b)many-one and into (c)one-one and onto (d)many-one and onto

f: N rarr N , where f(x) = x - (-1)^x . Then f is a)one-one and into b)many-one and into c)one-one and onto d)many-one and onto

f: NrarrN, where f(x)=x-(-1)^x . Then f is: (a)one-one and into (b)many-one and into (c)one-one and onto (d)many-one and onto

f: NrarrN, where f(x)=x-(-1)^x . Then f is: (a)one-one and into (b)many-one and into (c)one-one and onto (d)many-one and onto

f: NrarrN, where f(x)=x-(-1)^x . Then f is: (a)one-one and into (b)many-one and into (c)one-one and onto (d)many-one and onto

If f:N rarr N;f(x)=x-(-1)^(x) is (1) one one and into (2) Bijective (3) many one and into (4) many one and onto

Let f:[0,5] to [-1,5] , where f(x)={x^2-1,0 then f(x) is : (A) one-one and onto (B) one-one and into (C) many one and onto (D) many one and into

Let f:R rarr R, be defined as f(x)=e^(x^(2))+cos x, then is (a) one-one and onto (b) one-one and into ( c) many-one and onto (d) many-one and into

f(x) is a polynomial function, f: R rarr R, such that f(2x)=f'(x)f''(x). f(x) is (A) one-one and onto (B) one-one and into (C) many-one and onto (D) many-one and into

f(x) is a polynomial function, f: R rarr R, such that f(2x)=f'(x)f''(x). f(x) is (A) one-one and onto (B) one-one and into (C) many-one and onto (D) many-one and into